4x^2+19xy-5y^2=0

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Solution for 4x^2+19xy-5y^2=0 equation: 


Simplifying
4x2 + 19xy + -5y2 = 0

Reorder the terms:
19xy + 4x2 + -5y2 = 0

Solving
19xy + 4x2 + -5y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4x + -1y)(x + 5y) = 0


Subproblem 1
Set the factor '(4x + -1y)' equal to zero and attempt to solve:

Simplifying
4x + -1y = 0

Solving
4x + -1y = 0

Move all terms containing x to the left, all other terms to the right.

Add 'y' to each side of the equation.
4x + -1y + y = 0 + y

Combine like terms: -1y + y = 0
4x + 0 = 0 + y
4x = 0 + y
Remove the zero:
4x = y

Divide each side by '4'.
x = 0.25y

Simplifying
x = 0.25y

Subproblem 2
Set the factor '(x + 5y)' equal to zero and attempt to solve:

Simplifying
x + 5y = 0

Solving
x + 5y = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5y' to each side of the equation.
x + 5y + -5y = 0 + -5y

Combine like terms: 5y + -5y = 0
x + 0 = 0 + -5y
x = 0 + -5y
Remove the zero:
x = -5y

Simplifying
x = -5y
Solution
x = {0.25y, -5y}

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